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Anonymous, 24 May 2011
My dealer is so chintzy because they’re forced to buy their parts from select partners.
d6, 24 May 2011
Shareware.
Anonymous, 24 May 2011
my car dealer spent a fortune on "parts" for my 92 legend. they replaced the entire steering box assembly in the 2nd year of ownership. these parts are still in my car and the warranty still applies. he just cheated us out of hundreds of dollars.
Anonymous, 24 May 2011
Shareware.
Anonymous, 24 May 2011
My car dealer spent a fortune on "parts" for my 92 legend. they replaced the entire steering box assembly in the 2nd year of ownership. these parts are still in my car and the warranty still applies. he just cheated us out of hundreds of dollars.
Anonymous, 24 May 2011
Shareware.
Anonymous, 24 May 2011
Shareware.
Carlos.S.B, 24 May 2011
Sorry, I just don't think the steering box was replaceable as it is an integral part of the car
Anonymous, 24 May 2011
My dealer is so chintzy because they’re forced to buy their parts from select partners.
Anonymous, 24 May 2011
Right steering arm diameter and the upper ball joint. doh
Anonymous, 24 May 2011
Shareware.
jose luis, 24 May 2011
my car dealer spent a fortune on "parts" for my 92 legend. they replaced the entire steering box assembly in the 2nd year of ownership. these parts are still in my car and the warranty still applies. he just cheated us out of hundreds of dollars.
Anonymous, 24 May 2011
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.Q:
Python: using range() on a list of strings
I have a list of strings with numbers:
v = ['22', '35', '50', '23', '1', '11', '3', '0', '0']
I want to count the number of numbers in each string. The solution I found online is to convert it to a tuple and do range(len(v)). What I can't figure out is why I have to do this conversion.
A:
You need to put parentheses around the len(), and the single string will be converted to a tuple:
>>> v = ['22', '35', '50', '23', '1', '11', '3', '0', '0']
>>> len(v)
8
>>> range(len(v))
[0, 1, 2, 3, 4, 5, 6, 7]
>>> range(len(v))[:]
[0, 1, 2, 3, 4, 5, 6, 7]
A:
I'm not sure if I understand your problem correctly, but the answer to your question lies in the documentation of range():
range(start, stop[, step])
Return a list containing numbers from start to stop, incremented by step.
If step is omitted, it defaults to 1.
Here's a counter example:
>>> x = [4,3,2,1]
>>> range(x)
[1, 2, 3, 4]
>>> range(x)
[1, 2, 3, 4]
>>> range(x)
[1, 2, 3, 4]
So if you don't want a list of length 1, but a list with a length that is counting up, you need to specify the step as 0. Otherwise, it will count up and you'll get the length 1 list at the very end.
For creating lists, start with an empty list and count up:
>>> 
>>> 
>>> for i in range(0, len(v), 1):
...     print(v[i])
... 
22
35
50
23
1
11
3
0
0
So, adding parentheses to the construction of the list makes sure that you get a list with a length that is counting up:

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