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I am receiving a json string in Django. I am trying to convert it back to json object using json.loads but getting error: Expecting property name enclosed in double quotes: line 1 column 2 (char 1).This is the json object: journey: id: 1, name: Test Jour, journey_location: id: 2, name: 2, photo: https:p2.png, sublocation: Since I am working on an API. I converted the above json object to json string online. This is the json string I get:journey:id:1,name:Test Jour,journey_location🆔2,name:2,photo:https:p2.png,sublocation:I am trying to convert it back to json using json.loads() but getting error as mentioned above.I also make sure that I am using instead of but didnt work.Please guide me as to what I might be doing wrong. Back to Top Borislav HadzhievLast updated: Apr 24, 2022The Python JSONDecodeError: Expecting property name enclosed in doublequotes: line 1 column 2 (char 1) occurs when we try to parse an invalid JSONstring (e.g. single-quoted keys or values, or a trailing comma). Use theast.literal_eval() method to solve the error.Here is an example of how the error occurs.main.pyCopied!import json invalid_json = rname: Alice # ⛔️ json.decoder.JSONDecodeError: Expecting property name enclosed in double quotes: line 1 column 2 (char 1)result = json.loads(invalid_json)Notice that the string has a single-quoted key and value, which means that itisnt a valid JSON string.JSON (string) keys and values must be enclosed in double quotes.Rather, its just a Python dictionary thats wrapped in a string.You can solve the error by using the ast.literal_eval method to evaluate thestring that contains a Python literal.main.pyCopied!import ast invalid_json = rname: Alice result = ast.literal_eval(invalid_json)print(type(result)) # 👉️ <class dict> print(result) # 👉️ name: Aliceprint(resultname) # 👉️ AliceTheast.literal_evalmethod allows us to safely evaluate a string that contains a Python literal.The string may consist of strings, bytes, numbers, tuples, lists, dicts, sets, booleans and None.An alternative approach is to use the str.replace() method to replace allsingle quotes in the string with double quotes.main.pyCopied!import json invalid_json = rname: Alice valid_json = invalid_json.replace(, )print(valid_json) # 👉️ name: Alice my_dict = json.loads(valid_json) print(my_dict) # 👉️ name: Aliceprint(type(my_dict)) # 👉️ <class dict>However, this is very risky because the string could contain a single quote somewhere in its content, e.g. Its her.You can also use the ast.literal_eval method if your string contains atrailing comma.main.pyCopied!import ast invalid_json = rname: Alice, result = ast.literal_eval(invalid_json)print(type(result)) # 👉️ <class dict> print(result) # 👉️ name: Aliceprint(resultname) # 👉️ AliceThe trailing comma also makes the string invalid JSON, but Python dictionariesare allowed to have a trailing comma after the last key-value pair.Alternatively, you can try using the yaml.safe_load() method.Make sure you have pyyaml installed by running pip install pyyaml.main.pyCopied!import yaml invalid_json = rname: Alice, # 👈️ has trailing comma my_dict = yaml.safe_load(invalid_json) print(my_dict) # 👉️ name: Aliceprint(type(my_dict)) # 👉️ <class dict>Make sure the value you are trying to parse is a JSON string and has not beenalready parsed into a native Python object.If you need to parse a JSON string into a native Python object, you have to use the json.loads() method, and if you need to convert a Python object into a JSON string, you have to use the json.dumps() method.main.pyCopied!import json json_str = rname: Alice, age: 30 # ✅ parse JSON string to Python native dictmy_dict = json.loads(json_str)print(type(my_dict)) # 👉️ <class dict> # ✅ convert Python native dict to a JSON stringmy_json_str = json.dumps(my_dict)print(type(my_json_str)) # 👉️ <class str>The json.loads() method basically helps us load a Python native object (e.g. adictionary or a list) from a JSON string.The json.dumps methodconverts a Python object to a JSON formatted string.The JSONEncoder class supports the following objects and types by default.PythonJSONdictobjectlist, tuplearraystrstringint, float, int and float derived EnumsnumberTruetrueFalsefalseNonenullIf you arent sure what type of object a variable stores, use the built-intype() class.main.pyCopied!my_dict = name: Alice, age: 30print(type(my_dict)) # 👉️ <class dict>print(isinstance(my_dict, dict)) # 👉️ True my_str = hello worldprint(type(my_str)) # 👉️ <class str>print(isinstance(my_str, str)) # 👉️ TrueThe type class returnsthe type of an object.The isinstancefunction returns True if the passed in object is an instance or a subclass ofthe passed in class.Conclusion #The Python JSONDecodeError: Expecting property name enclosed in doublequotes: line 1 column 2 (char 1) occurs when we try to parse an invalid JSONstring (e.g. single-quoted keys or values, or a trailing comma). Use theast.literal_eval() method to solve the error.
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