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Academia.edu uses cookies to personalize content, tailor ads and improve the user experience.By using our site, you agree to our collection of information through the use of cookies.To learn more, view our Privacy Policy. The blue police cars would be difficult to see under sodium streetlamps. Blue is the complementary color to yellow. Blue + yellow = white. Under normal illumination, blue cars absorb the complementary color to blue (which is yellow), reflecting blue light. The blue cars appear black when illuminated by yellow light, because the paint absorbs that light, and there is no blue light to reflect. This is discussed on pages 505-506 and 509-511. You can help us out by revising, improving and updatingthis answer. Update this answerAfter you claim an answer youll have 24 hours to send in a draft. An editorwill review the submission and either publish your submission or provide feedback.Next AnswerChapter 27 - Think and Explain - Page 517-518: 48Previous AnswerChapter 27 - Think and Explain - Page 517-518: 46 404 The page you are looking for was not found. Back to Home 3rd EditionMary L. Boas10th EditionDavid Halliday, Jearl Walker, Robert Resnick14th EditionHugh D. Young, Roger A. Freedman10th EditionJulio de Paula, Peter Atkins Conceptual Physics was written by and is associated to the ISBN: 9780321909107. Since 81 problems in chapter 27 have been answered, more than 723140 students have viewed full step-by-step solutions from this chapter. This expansive textbook survival guide covers the following chapters and their solutions. Chapter 27 includes 81 full step-by-step solutions. This textbook survival guide was created for the textbook: Conceptual Physics, edition: 12. parallel any symbol average (indicated by a bar over a symbol—e.g., v¯ is average velocity) °C Celsius degree °F Fahrenheit degree 10th EditionDavid Halliday, Jearl Walker, Robert Resnick14th EditionHugh D. Young, Roger A. Freedman3rd EditionMary L. Boas4th EditionRandall D. KnightAcademia.edu uses cookies to personalize content, tailor ads and improve the user experience.By using our site, you agree to our collection of information through the use of cookies.To learn more, view our Privacy Policy. 1. 1 1 . 333 = 0 . 750 1 1 . 333 = 0 . 750 size 1211 . 333=0 . 750 6. 0 . 516º 0 . 516º size 120 . 516° 8. 1 . 22 × 10 − 6 m 1 . 22 × 10 − 6 m size 121 . 22 times 10 rSup size 8 - 6 'm 12. 2 . 06º 2 . 06º size 122 . 06° 14. 16. 18. For small angles sinθ−tanθ≈θ(in radians)sinθ−tanθ≈θ(in radians) size 12sinθ - tanθ approx θ' ( in'radians ) .For two adjacent fringes we have, d sin θ m = mλ d sin θ m = mλ size 12d'sinθ rSub size 8m =mλ and d sin θ m + 1 = m + 1 λ d sin θ m + 1 = m + 1 λ size 12d'sin θ rSub size 8m+1 = left (m+1 right )λ Subtracting these equations gives d sin θ m + 1 − sin θ m = m + 1 − m λ d θ m + 1 − θ m = λ tan θ m = y m x ≈ θ m ⇒ d y m + 1 x − y m x = λ d Δ y x = λ ⇒ Δ y = xλ d d sin θ m + 1 − sin θ m = m + 1 − m λ d θ m + 1 − θ m = λ tan θ m = y m x ≈ θ m ⇒ d y m + 1 x − y m x = λ d Δ y x = λ ⇒ Δ y = xλ d alignl stack size 12d left (sinθ rSub size 8m+1 - sinθ rSub size 8m right )= left left (m+1 right ) - m right λ #d left (θ rSub size 8m+1 - θ lSub size 8m right )=λ #tanθ rSub size 8m = y rSub size 8m over x approx θ lSub size 8m drarrow d left ( y rSub size 8m+1 over x - y rSub size 8m over x right )=λ #d Δy over x =λ drarrow underline Δy= xλ over d 21. 5 . 97º 5 . 97º size 125 . 97° 23. 8 . 99 × 10 3 8 . 99 × 10 3 size 128 . 99 times 10 rSup size 83 27. ( a ) 11.8º , 12.5º , 14.1º , 19.2º ( a ) 11.8º , 12.5º , 14.1º , 19.2º alignl stack size 12 ( a ) '11 . 8°,'12 . 5°,'14 . 1°,'19 . 2° # size 12 ( b ) '24 . 2°,'25 . 7°,'29 . 1°,'41 . 0° ( b ) 24.2º , 25.7º , 29.1º , 41.0º ( b ) 24.2º , 25.7º , 29.1º , 41.0º alignl stack size 12 ( a ) '11 . 8°,'12 . 5°,'14 . 1°,'19 . 2° # size 12 ( b ) '24 . 2°,'25 . 7°,'29 . 1°,'41 . 0° (c) Decreasingthenumberoflinespercentimeterbyafactorof xmeansthattheangleforthex‐ordermaximumisthesameastheoriginalangleforthefirst-ordermaximum. 29. 31. 28.7º 28.7º size 1228 . 69° 33. 43 . 2º 43 . 2º size 1243 . 2° 35. 90 . 0º 90 . 0º size 1290 . 0° 37. (a) The longest wavelength is 333.3 nm, which is not visible. (b) 333 nm (UV) (c) 6.58×103cm6.58×103cm size 126 . 58 times 10 rSup size 83 'cm 39. 1 . 13 × 10 − 2 m 1 . 13 × 10 − 2 m size 121 . 13 times 10 rSup size 8 - 2 'm 41. (a) 42.3 nm (b) Not a visible wavelength Thenumberofslitsinthisdiffractiongratingistoolarge.Etchinginintegratedcircuitscanbedonetoaresolutionof50nm,soslitseparationsof400nmareatthelimitofwhatwecandotoday.Thislinespacingistoosmalltoproducediffractionoflight.43. (a) 33.4º33.4º size 1233 . 4° (b) No 45. (a) 1.35×10−6m1.35×10−6m size 121 . 35 times 10 rSup size 8 - 6 'm (b) 69.9º69.9º size 1269 . 9° 49. (a) 9.04º9.04º size 129 . 04° (b) 12 51. (a) 0.0150º0.0150º size 120 . 0150° (b) 0.262 mm (c) This distance is not easily measured by human eye, but under a microscope or magnifying glass it is quite easily measurable. 53. (a) 30.1º30.1º size 1230 . 1° (b) 48.7º48.7º size 1248 . 7° (c) No (d) 2θ1=(2)(14.5º)=29º,θ2−θ1=30.05º−14.5º=15.56º2θ1=(2)(14.5º)=29º,θ2−θ1=30.05º−14.5º=15.56º size 122θ rSub size 81 = ( 2 ) ( 14 . 5° ) =29°,~θ rSub size 82 - θ rSub size 81 =30 . 05° - 14 . 5°=15 . 56° . Thus, 29º≈(2)(15.56º)=31.1º29º≈(2)(15.56º)=31.1º size 1229° approx ( 2 ) ( 15 . 56° ) =31 . 1° .55. 23.6º23.6º size 1223 . 6° and 53.1º53.1º size 1253 . 1° 57. (a) 1.63×10−4rad1.63×10−4rad size 121 . 63 times 10 rSup size 8 - 4 'rad (b) 326 ly59. 1 . 46 × 10 − 5 rad 1 . 46 × 10 − 5 rad size 121 . 46 times 10 rSup size 8 - 5 'rad 61. (a) 3.04×10−7rad3.04×10−7rad size 123 . 04 times 10 rSup size 8 - 7 'rad (b) Diameter of 235 m235 m65. (a) Yes. Should easily be able to discern. (b) The fact that it is just barely possible to discern that these are separate bodies indicates the severity of atmospheric aberrations. 80. 4 . 42 × 10 − 5 m 4 . 42 × 10 − 5 m size 124 . 42 times 10 rSup size 8 - 5 'm 82. The oil film will appear black, since the reflected light is not in the visible part of the spectrum. 84. 45 . 0º 45 . 0º size 1245 . 0° 86. 45 . 7 mWm 2 45 . 7 mWm 2 size 1245 . 7'mWm rSup size 82 88. 90 . 0% 90 . 0% size 1290 . 0% 90. I 0 I 0 size 12I rSub size 80 92. 48 . 8º 48 . 8º size 1248 . 8° 94. 41 . 2º 41 . 2º size 1241 . 2° 96. (a) 1.92, not diamond (Zircon) (b) 55.2º55.2º size 1255 . 2° 98. B 2 = 0 . 707 B 1 B 2 = 0 . 707 B 1 size 12B rSub size 82 =0 . 707B rSub size 81 100. (a) 2.07×10-22.07×10-2 °Cs(b) Yes, the polarizing filters get hot because they absorb some of the lost energy from the sunlight.
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