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IF you are looking for the notes of maths class 9 all chapters then you are on the right page because here we have shared the 9th Class Maths Notes pdf download online.below are the notes of all chapters of Mathematics class 9 listed with their download link but you can also read them online.Download Math Notes in Android App Unit No. Unit Name Download Link 1 Metrics And Determinants Download 2 Real and Complex Numbers Download 3 Logarithms Download 4 Algebraic Expressions and Algebraic Formulas Download 5 Algebraic Manipulation Download 6 Algebraic Manipulation Download 7 Linear Equations and Inequalities Download 8 Linear Graphs and Their Application Download 9 Introduction to Coordinate Geometry Download 10 Congruent Triangles Download 11 Parallelograms and Triangles Download 12 Line Bisectors and Angels Bisectors Download 13 Sides and Angles of a Triangle Download 14 Ratio and Proportion Download 15 Pythagoras Theorem Download 16 Theorems Related to Area Download 17 Practical Geometry-Triangles Download : You may also like: You can give your opinion or any question you have to ask below in the comment section area. Already 26 people have commented on this post. Be the next one on the list. We will try to respond to your comment as soon as possible. Please do not spam in the comment section otherwise your comment will be deleted and IP banned. Home9th Class Math Notes9th Class Math Notes Full Book Exercise Solutions 9th Class Math Notestaleemcity4 Related Articles1. leftbeginarrayll0 & 0 0 & 0endarrayright isa. An identity matrix w.r.t multiplicationb. A column matrixc. An identity matrix w.r.t additiond. A row matrix Answer: An identity matrix w.r.t addition Explanation:Zero (0) is called additive identity. Thus Zero or Null matrix is additive identity matrix. 2. The matrix leftbeginarraycc4 & 0 0 & -12endarrayright isa. A scalar matrixb. quad 2 times 3 matrixc. A diagonal matrixd. None of these Answer: A diagonal matrix Explanation:A square matrix on which all elements are zero except diagonal elements is known as diagonal matrix. 3. If A=leftbeginarraycc-1 & -2 3 & 1endarrayright , then adj A is equal toa. quadleftbeginarraycc-1 & -2 3 & 1endarrayright b. quadleftbeginarraycc1 & 2 -3 & -1endarrayright c. leftbeginarraycc-1 & 2 3 & 1endarrayright d. quadleftbeginarraycc1 & -2 3 & 1endarrayright Answer: quadleftbeginarraycc-1 & -2 3 & 1endarrayright Explanation:Let A=leftbeginarraylla & b c & dendarrayright As change the places of a and d with each other and change the signs of b and c . So Adj A=leftbeginarrayccd & -b -c & aendarrayright 4. If A =leftbeginarrayll2 & 3 3 & 4endarrayright then A^-1= a. quadleftbeginarraycc4 & 3 -3 & 2endarrayright b. quadleftbeginarraycc4 & -3 -3 & 2endarrayright c. quadleftbeginarraycc-2 & 3 3 & -4endarrayright d. quadleftbeginarraycc-4 & 3 3 & -2endarrayright Answer: Explanation: A=leftbeginarrayll2 & 3 3 & 4endarrayright A^-1=frac1|A| Adj A |A|=left|beginarrayll2 & 3 3 & 4endarrayright| |A|=8-9 |A|=-1 eq 0 Adj A=leftbeginarraycc4 & -3 -3 & 2endarrayright Put the values in equation A^-1=frac1-1leftbeginarraycc4 & -3 -3 & 2endarrayright A^-1=-leftbeginarraycc4 & -3 -3 & 2endarrayright A^-1=leftbeginarraycc-4 & 3 3 & -2endarrayright 5. For what value of d is the 2 times 2 matrix leftbeginarraycc1 & 1.5 2 & dendarrayright not invertible?a. -0.6 b. 0c. 0.6 d. 3 Answer: 6 Explanation: Singular matrix is also called NOT invertible.Thus |A|=0 left|beginarrayll5 & 1.5 2 & dendarrayright|=0 5 times d-2 times 1.5=0 5d-3=0 5d=3 d=frac35 d=0.6 6. Suppose A and B are 2 times 5 matrices, which of the following are the dimensions of the matrix A+B ?a. 2 times 5 b. 10 times 10 c. quad 7 times 7 d. quad 7 times 1 Answer: 2 times 5 Explanation:For Addition of two matrices, the dimensions of the matrices must be same. Thus A+B have the dimensions 2 times 5 7.Which of the following is the multiplicative inverse of leftbeginarrayll1 & 2 0 & 1endarrayright isa. quadleftbeginarrayll1 & 2 0 & 1endarrayright b. quadleftbeginarraycc1 & -2 0 & 1endarrayright c. quadleftbeginarraycc-1 & 2 0 & 1endarrayright d. quadleftbeginarrayll1 & -2 0 & -1endarrayright Answer: quadleftbeginarraycc1 & -2 0 & 1endarrayright Explanation:Let A=leftbeginarrayll1 & 2 0 & 1endarrayright A^-1=frac1|A| Adj A Let |A|=left|beginarrayll1 & 2 0 & 1endarrayright| |A|=1-0 |A|=1 eq 0 Adj A=leftbeginarraycc1 & -2 0 & 1endarrayright Put the values in equation A^-1=frac11leftbeginarraycc1 & -2 0 & 1endarrayright A^-1=leftbeginarraycc1 & -2 0 & 1endarrayright 8. The determinant of leftbeginarraycc4 & -1 -9 & 2endarrayright isa. 17b. 1c. -1 d. quad-17 Answer: |A|=-1 Explanation:Let |A|=left|beginarrayll4 & -1 -9 & 2endarrayright| |A|=(4)(2)-(-9)(-1) |A|=8-9 |A|=-1
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