The Bible As Literature An Introduction.pdf
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Category:Classical studiesQ:
C++: copy constructor called on class with private constructor
I've got a class with private constructor and public member function of this type.
Class:
#pragma once
#include 
#include 
#include 
class A{
    public:
        A();
        std::string test(std::string n){ return n; }
    private:
        std::string some_s;
};
I also have a class, which has private copy constructor and private assignment operator
Class B:
#pragma once
#include 
#include 
#include 
class B{
    public:
        B();
        B(const A& other);
        const A &operator=(const A &other);
    private:
        A b;
};
Constructor:
B::B(){}
And assignment operator:
B &B::operator=(const B &other) {
    b = other.b;
    return *this;
}
It seems to me that compiler should call the copy constructor during the copy assignment. 
When I am testing it with
std::array arr;
and
std::array barr = std::make_array(arr.begin(), arr.end());
And compiler ignores the fact that B constructor is private (which I would like it to do) and does what it would do with class A.
A:
Please do not use the private constructor name (B::B()) because it is a protected name. I am not sure why you are providing two constructors. You can simply use the default copy constructor:
#pragma once
#include 
#include 
#include 
class A
ac619d1d87

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